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Django Fileアップロード例

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Django Fileアップロード例

Django | Python |

fileuptest/views.py

  1. from django.http import HttpResponse
  2. from django.template import Context, loader
  3. from django.forms import *
  4.  
  5. def index(request):
  6.     msg = 
  7.     if request.method == 'POST':
  8.         form = UploadFileForm(request.POST, request.FILES)
  9.         if form.is_valid():
  10.             updir = r'c:\\website\\django\\mysite\\upload\\' + form.cleaned_data['title']
  11.             destination = open(updir, 'wb+')
  12.             upfile = request.FILES['file']
  13.             for chunk in upfile.chunks():
  14.                 destination.write(chunk)
  15.             destination.close()
  16.             msg = 'Uploaded.'
  17.     else:
  18.         form = UploadFileForm()
  19.  
  20.     t = loader.get_template('fileuptest/index.html')
  21.     c = Context()
  22.     c['form'] = form
  23.     c['msg'] = msg
  24.     return HttpResponse(t.render(c))
  25.  
  26. class UploadFileForm(Form):
  27.     title = CharField(max_length=50)
  28.     file  = FileField()

template/fileuptest/index.html

  1. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
  2. <html>
  3. <head>
  4.   <META http-equiv="Content-Type" content="text/html; charset=UTF-8">
  5.   <script type="text/javascript">
  6.   </script>
  7. </head>
  8. <body>
  9.   テンプレート:Msg
  10.   <form enctype="multipart/form-data" action='/fileuptest/' method='POST'>
  11.     <table>
  12.     テンプレート:Form
  13.     </table>    
  14.     <input type='submit' value=" 添 付 ">
  15.   </form>
  16. </body>
  17. </html>

結果

0385 fileup form01.jpg

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